3.18.99 \(\int \frac {(1-2 x)^{5/2} (3+5 x)}{(2+3 x)^4} \, dx\)

Optimal. Leaf size=101 \[ \frac {(1-2 x)^{7/2}}{63 (3 x+2)^3}-\frac {53 (1-2 x)^{5/2}}{189 (3 x+2)^2}+\frac {265 (1-2 x)^{3/2}}{567 (3 x+2)}+\frac {530}{567} \sqrt {1-2 x}-\frac {530 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{81 \sqrt {21}} \]

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Rubi [A]  time = 0.02, antiderivative size = 101, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {78, 47, 50, 63, 206} \begin {gather*} \frac {(1-2 x)^{7/2}}{63 (3 x+2)^3}-\frac {53 (1-2 x)^{5/2}}{189 (3 x+2)^2}+\frac {265 (1-2 x)^{3/2}}{567 (3 x+2)}+\frac {530}{567} \sqrt {1-2 x}-\frac {530 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{81 \sqrt {21}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((1 - 2*x)^(5/2)*(3 + 5*x))/(2 + 3*x)^4,x]

[Out]

(530*Sqrt[1 - 2*x])/567 + (1 - 2*x)^(7/2)/(63*(2 + 3*x)^3) - (53*(1 - 2*x)^(5/2))/(189*(2 + 3*x)^2) + (265*(1
- 2*x)^(3/2))/(567*(2 + 3*x)) - (530*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(81*Sqrt[21])

Rule 47

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + 1)), x] - Dist[(d*n)/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n - 1), x], x] /; FreeQ[{a, b, c, d},
x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && LtQ[m, -1] &&  !(IntegerQ[n] &&  !IntegerQ[m]) &&  !(ILeQ[m + n + 2, 0
] && (FractionQ[m] || GeQ[2*n + m + 1, 0])) && IntLinearQ[a, b, c, d, m, n, x]

Rule 50

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[((a + b*x)^(m + 1)*(c + d*x)^n)/(b*
(m + n + 1)), x] + Dist[(n*(b*c - a*d))/(b*(m + n + 1)), Int[(a + b*x)^m*(c + d*x)^(n - 1), x], x] /; FreeQ[{a
, b, c, d}, x] && NeQ[b*c - a*d, 0] && GtQ[n, 0] && NeQ[m + n + 1, 0] &&  !(IGtQ[m, 0] && ( !IntegerQ[n] || (G
tQ[m, 0] && LtQ[m - n, 0]))) &&  !ILtQ[m + n + 2, 0] && IntLinearQ[a, b, c, d, m, n, x]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 78

Int[((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> -Simp[((b*e - a*f
)*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(f*(p + 1)*(c*f - d*e)), x] - Dist[(a*d*f*(n + p + 2) - b*(d*e*(n + 1)
+ c*f*(p + 1)))/(f*(p + 1)*(c*f - d*e)), Int[(c + d*x)^n*(e + f*x)^(p + 1), x], x] /; FreeQ[{a, b, c, d, e, f,
n}, x] && LtQ[p, -1] && ( !LtQ[n, -1] || IntegerQ[p] ||  !(IntegerQ[n] ||  !(EqQ[e, 0] ||  !(EqQ[c, 0] || LtQ
[p, n]))))

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin {align*} \int \frac {(1-2 x)^{5/2} (3+5 x)}{(2+3 x)^4} \, dx &=\frac {(1-2 x)^{7/2}}{63 (2+3 x)^3}+\frac {106}{63} \int \frac {(1-2 x)^{5/2}}{(2+3 x)^3} \, dx\\ &=\frac {(1-2 x)^{7/2}}{63 (2+3 x)^3}-\frac {53 (1-2 x)^{5/2}}{189 (2+3 x)^2}-\frac {265}{189} \int \frac {(1-2 x)^{3/2}}{(2+3 x)^2} \, dx\\ &=\frac {(1-2 x)^{7/2}}{63 (2+3 x)^3}-\frac {53 (1-2 x)^{5/2}}{189 (2+3 x)^2}+\frac {265 (1-2 x)^{3/2}}{567 (2+3 x)}+\frac {265}{189} \int \frac {\sqrt {1-2 x}}{2+3 x} \, dx\\ &=\frac {530}{567} \sqrt {1-2 x}+\frac {(1-2 x)^{7/2}}{63 (2+3 x)^3}-\frac {53 (1-2 x)^{5/2}}{189 (2+3 x)^2}+\frac {265 (1-2 x)^{3/2}}{567 (2+3 x)}+\frac {265}{81} \int \frac {1}{\sqrt {1-2 x} (2+3 x)} \, dx\\ &=\frac {530}{567} \sqrt {1-2 x}+\frac {(1-2 x)^{7/2}}{63 (2+3 x)^3}-\frac {53 (1-2 x)^{5/2}}{189 (2+3 x)^2}+\frac {265 (1-2 x)^{3/2}}{567 (2+3 x)}-\frac {265}{81} \operatorname {Subst}\left (\int \frac {1}{\frac {7}{2}-\frac {3 x^2}{2}} \, dx,x,\sqrt {1-2 x}\right )\\ &=\frac {530}{567} \sqrt {1-2 x}+\frac {(1-2 x)^{7/2}}{63 (2+3 x)^3}-\frac {53 (1-2 x)^{5/2}}{189 (2+3 x)^2}+\frac {265 (1-2 x)^{3/2}}{567 (2+3 x)}-\frac {530 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{81 \sqrt {21}}\\ \end {align*}

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Mathematica [C]  time = 0.02, size = 42, normalized size = 0.42 \begin {gather*} \frac {(1-2 x)^{7/2} \left (\frac {2401}{(3 x+2)^3}-848 \, _2F_1\left (3,\frac {7}{2};\frac {9}{2};\frac {3}{7}-\frac {6 x}{7}\right )\right )}{151263} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((1 - 2*x)^(5/2)*(3 + 5*x))/(2 + 3*x)^4,x]

[Out]

((1 - 2*x)^(7/2)*(2401/(2 + 3*x)^3 - 848*Hypergeometric2F1[3, 7/2, 9/2, 3/7 - (6*x)/7]))/151263

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IntegrateAlgebraic [A]  time = 0.23, size = 79, normalized size = 0.78 \begin {gather*} \frac {2 \left (540 (1-2 x)^3-5247 (1-2 x)^2+14840 (1-2 x)-12985\right ) \sqrt {1-2 x}}{81 (3 (1-2 x)-7)^3}-\frac {530 \tanh ^{-1}\left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )}{81 \sqrt {21}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[((1 - 2*x)^(5/2)*(3 + 5*x))/(2 + 3*x)^4,x]

[Out]

(2*(-12985 + 14840*(1 - 2*x) - 5247*(1 - 2*x)^2 + 540*(1 - 2*x)^3)*Sqrt[1 - 2*x])/(81*(-7 + 3*(1 - 2*x))^3) -
(530*ArcTanh[Sqrt[3/7]*Sqrt[1 - 2*x]])/(81*Sqrt[21])

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fricas [A]  time = 0.73, size = 89, normalized size = 0.88 \begin {gather*} \frac {265 \, \sqrt {21} {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )} \log \left (\frac {3 \, x + \sqrt {21} \sqrt {-2 \, x + 1} - 5}{3 \, x + 2}\right ) + 21 \, {\left (1080 \, x^{3} + 3627 \, x^{2} + 2983 \, x + 713\right )} \sqrt {-2 \, x + 1}}{1701 \, {\left (27 \, x^{3} + 54 \, x^{2} + 36 \, x + 8\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)/(2+3*x)^4,x, algorithm="fricas")

[Out]

1/1701*(265*sqrt(21)*(27*x^3 + 54*x^2 + 36*x + 8)*log((3*x + sqrt(21)*sqrt(-2*x + 1) - 5)/(3*x + 2)) + 21*(108
0*x^3 + 3627*x^2 + 2983*x + 713)*sqrt(-2*x + 1))/(27*x^3 + 54*x^2 + 36*x + 8)

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giac [A]  time = 1.13, size = 93, normalized size = 0.92 \begin {gather*} \frac {265}{1701} \, \sqrt {21} \log \left (\frac {{\left | -2 \, \sqrt {21} + 6 \, \sqrt {-2 \, x + 1} \right |}}{2 \, {\left (\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}\right )}}\right ) + \frac {40}{81} \, \sqrt {-2 \, x + 1} + \frac {1467 \, {\left (2 \, x - 1\right )}^{2} \sqrt {-2 \, x + 1} - 6020 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} + 6125 \, \sqrt {-2 \, x + 1}}{324 \, {\left (3 \, x + 2\right )}^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)/(2+3*x)^4,x, algorithm="giac")

[Out]

265/1701*sqrt(21)*log(1/2*abs(-2*sqrt(21) + 6*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) + 40/81*sqrt(-2*x
+ 1) + 1/324*(1467*(2*x - 1)^2*sqrt(-2*x + 1) - 6020*(-2*x + 1)^(3/2) + 6125*sqrt(-2*x + 1))/(3*x + 2)^3

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maple [A]  time = 0.01, size = 66, normalized size = 0.65 \begin {gather*} -\frac {530 \sqrt {21}\, \arctanh \left (\frac {\sqrt {21}\, \sqrt {-2 x +1}}{7}\right )}{1701}+\frac {40 \sqrt {-2 x +1}}{81}+\frac {-\frac {326 \left (-2 x +1\right )^{\frac {5}{2}}}{9}+\frac {12040 \left (-2 x +1\right )^{\frac {3}{2}}}{81}-\frac {12250 \sqrt {-2 x +1}}{81}}{\left (-6 x -4\right )^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-2*x+1)^(5/2)*(5*x+3)/(3*x+2)^4,x)

[Out]

40/81*(-2*x+1)^(1/2)+8/3*(-163/12*(-2*x+1)^(5/2)+1505/27*(-2*x+1)^(3/2)-6125/108*(-2*x+1)^(1/2))/(-6*x-4)^3-53
0/1701*arctanh(1/7*21^(1/2)*(-2*x+1)^(1/2))*21^(1/2)

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maxima [A]  time = 1.22, size = 101, normalized size = 1.00 \begin {gather*} \frac {265}{1701} \, \sqrt {21} \log \left (-\frac {\sqrt {21} - 3 \, \sqrt {-2 \, x + 1}}{\sqrt {21} + 3 \, \sqrt {-2 \, x + 1}}\right ) + \frac {40}{81} \, \sqrt {-2 \, x + 1} + \frac {2 \, {\left (1467 \, {\left (-2 \, x + 1\right )}^{\frac {5}{2}} - 6020 \, {\left (-2 \, x + 1\right )}^{\frac {3}{2}} + 6125 \, \sqrt {-2 \, x + 1}\right )}}{81 \, {\left (27 \, {\left (2 \, x - 1\right )}^{3} + 189 \, {\left (2 \, x - 1\right )}^{2} + 882 \, x - 98\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)^(5/2)*(3+5*x)/(2+3*x)^4,x, algorithm="maxima")

[Out]

265/1701*sqrt(21)*log(-(sqrt(21) - 3*sqrt(-2*x + 1))/(sqrt(21) + 3*sqrt(-2*x + 1))) + 40/81*sqrt(-2*x + 1) + 2
/81*(1467*(-2*x + 1)^(5/2) - 6020*(-2*x + 1)^(3/2) + 6125*sqrt(-2*x + 1))/(27*(2*x - 1)^3 + 189*(2*x - 1)^2 +
882*x - 98)

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mupad [B]  time = 0.06, size = 80, normalized size = 0.79 \begin {gather*} \frac {40\,\sqrt {1-2\,x}}{81}-\frac {530\,\sqrt {21}\,\mathrm {atanh}\left (\frac {\sqrt {21}\,\sqrt {1-2\,x}}{7}\right )}{1701}+\frac {\frac {12250\,\sqrt {1-2\,x}}{2187}-\frac {12040\,{\left (1-2\,x\right )}^{3/2}}{2187}+\frac {326\,{\left (1-2\,x\right )}^{5/2}}{243}}{\frac {98\,x}{3}+7\,{\left (2\,x-1\right )}^2+{\left (2\,x-1\right )}^3-\frac {98}{27}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((1 - 2*x)^(5/2)*(5*x + 3))/(3*x + 2)^4,x)

[Out]

(40*(1 - 2*x)^(1/2))/81 - (530*21^(1/2)*atanh((21^(1/2)*(1 - 2*x)^(1/2))/7))/1701 + ((12250*(1 - 2*x)^(1/2))/2
187 - (12040*(1 - 2*x)^(3/2))/2187 + (326*(1 - 2*x)^(5/2))/243)/((98*x)/3 + 7*(2*x - 1)^2 + (2*x - 1)^3 - 98/2
7)

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sympy [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-2*x)**(5/2)*(3+5*x)/(2+3*x)**4,x)

[Out]

Timed out

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